Question

The area of a man's foot is ${80cm}^2$. How much pressure will the man exert on the ground standing, if his mass is 80 kg?

Answer 1

Weight $=80$ kgf =$80\times 9.8$ N

Mass of two feet $=2\times (80\times {10}^{-2})m^2$

$Pressure=\frac{force}{area}$ =$\frac{80\times 9.8}{160\times {10}^{-4}}$ =$4.9\times {10}^{4}Pa$