Question

The area of a parallelogram is $70d{m}^2$ and its altitude is $7$ dm, then the perimeter of a rectangle of equal area standing on the same base is

• A. $40$ dm
• B. $28$ dm
• C. $34$ dm
• D. $17$ dm

Answer 1

The correct option is C $34$ dm

Area of parallelogram $=$ base $\times$ height
$70=$ base $\times 7$
Base $=10$ dm
Area of rectangle $=$ Area of parallelogram $=70d{m}^2$
Length $\times$ breadth $=70d{m}^2$
$10\times$ breadth $=70d{m}^2$
Breadth $=7$ dm
Perimeter $=2(l+b)$
$=2(10+7)$
$=34$ dm