Question

The area of a parallelogram is $y$ $c{m}^2$ and its height is $hcm$. The base of another parallelogram is $xcm$ more than the base of the first parallelogram and its area is twice the area of the first. Find, in terms of $y,h$ and $x$, the expression for the height of the second parallelogram.

• A. $\frac{hy}{yh-x}$
• B. $\frac{y}{y-xh}$
• C. $\frac{2hy}{y+xh}$
• D. None of these

Answer 1

The correct option is C $\frac{2hy}{y+xh}$

Base of 1st parallelogram = $\frac{y}{h}$ cm
$\Rightarrow$ Base of 2nd parallelogram = $\left(\frac{y}{h}+x\right)$
and $\left(\frac{y}{h}+x\right)\times height=2y$
$\Rightarrow height=\frac{2hy}{y+xh}$