The area of a rectangle is $4 x^{4} - 9 y^{2}$ sq. units. Which factor could represent the length times width?

(2 x^{2} - 3 y) (2 x^{2} + 3 y)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2 x^{2} + 3 y) (2 x^{2} + 3 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 x - 3 y) (2 x - 3 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 x + 3 y) (2 x - 3 y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(2 x^{2} - 3 y) (2 x^{2} + 3 y)$
The area of is $4 x^{4} - 9 y^{2} \Rightarrow (2 x)^{2} - (3 y)^{2} \Rightarrow (2 x^{2} + 3 y) \times (2 x^{2} - 3 y)$ which is same as the area of rectangle
$l \times b ∴$ The product of length times width is $= (2 x^{2} + 3 y) \times (2 x^{2} - 3 y)$ .

Suggest Corrections

Similar questions

(2 x - 3 y) (2 x + 3 y) = (2 x)^{2} - (3 y)^{2}

2 x^{2} - 18 y^{2}

(2 x + 3 y) (2 x - 3 y)

Simplify: $(2 x - 3 y) (2 x + 3 y)$

(2 x + 3 y)^{2}

(2 x - 3 y)^{2}

(2 x + 3 y) (2 x - 3 y)

Join BYJU'S Learning Program