Question

The area of a rectangle is $460{\text{cm}}^2.$ If the length is $15\%$ more than the breadth, what is the breadth of the rectangle?

Answer 1

Let the breadth of the rectangle be $b$. So, the length of the rectangle will be,

$\begin{array}{cc}l& =\left(1+\frac{15}{100}\right)b\\ & =\frac{23b}{20}\end{array}$

Now, area is equal to product of length and breadth so,

$\begin{array}{cc}l\times b& =460\\ \frac{23b}{20}\times b& =460\\ b^2& =\frac{20}{23}\times 460\\ b^2& =400\\ b& =20\text{cm}\end{array}$

So, the breadth of the rectangle is equal to $20\text{cm}.$