Given, length = \(\frac{5}{8}~m\) and breadth = \(\frac{2}{15}~m\).
We know that, area of a rectangle of length \(l\) and breadth \(b\) is '\(l\times b\)'.
So, the area of the given rectangle = \(\frac{5}{8}~m\times \frac{2}{15}~m\)
=\(\frac{1}{12}~m^2\)