Question

The area of a rectangular field is $465m^2$ and its length is $31m$. Find the

a) breadth of the field

b) cost of fencing it at the rate of ₹$15.50permetre$.

Answer 1

Step 1 - Given, area of rectangle $=465m^2$ and length $=31m$

Step 2 - Area of rectangle $=length\times breadth$

$$\begin{gathered} 465=31\times b \\ \frac{465}{31}=b \\ 15m=b \end{gathered}$$

Hence, the breadth of the rectangle is $15m.$

Step 3 - To find the cost of fencing it at the rate of ₹ $15.50permetre$ firstly we have to find the perimeter of the rectangle.

Perimeter of rectangle $$\begin{gathered} =2\times \left(length+breadth\right) \\ =2\times \left(31+15\right) \\ =2\times \left(46\right) \\ =92m \end{gathered}$$

Step 4 - Cost of fencing $$\begin{gathered} =15.50\times 92 \\ =1426 \end{gathered}$$

Hence, the cost of fencing is ₹$1426$.