The area of a rectangular field of breadth $48$ m is the same as the area of as square field of side $60$ m. Find the perimeter of the rectangular field.

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Solution

Area of rectangle $=$ Area of square
$\Rightarrow l \times 48 = 60 \times 60 \Rightarrow l = 75 c m$
Perimeter of rectangle $= 2 (l + b) = 246 m$

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The area of a rectangular field of breadth 48 m is the same as the area of as square field of side 60 m. Find the perimeter of the rectangular field.

Area of rectangle = Area of square⇒l×48=60×60⇒l=75cmPerimeter of rectangle =2(l+b)=246m

The area of a rectangular field of breadth $48$ m is the same as the area of as square field of side $60$ m. Find the perimeter of the rectangular field.

Area of rectangle $=$ Area of square
$\Rightarrow l \times 48 = 60 \times 60 \Rightarrow l = 75 c m$
Perimeter of rectangle $= 2 (l + b) = 246 m$