Question

The area of a regular hexagon (in sq.m)of side $4$ meters is

• A. $6\sqrt{3}$
• B. $9\sqrt{2}$
• C. $12\sqrt{6}$
• D. $24\sqrt{3}$

Answer 1

The correct option is D $24\sqrt{3}$

Area of the regular hexagon of side 4 meters $=6\times$ area of an equilateral triangle of side 4 meters
$=6\times \frac{\sqrt{3}}{4}\times 4^2=24\sqrt{3}$