The area of a rhombus is 36 cm² and the length of one of its diagonals is 6 cm. The length of the second diagonal is

(a) 6 cm
(b) $6 \sqrt{2}$ cm
(c) 12 cm
(d) none of these

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Solution

(c) 12 cm

Area of the rhombus = $\frac{1}{2}$ × (Product of the diagonals)
Given:
Length of one diagonal = 6 cm
Area of the rhombus = 36 cm²

∴ Length of the other diagonal = $(\frac{36 \times 2}{6})$ cm = 12 cm

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The area of a rhombus is 36 cm2 and the length of one of its diagonals is 6 cm. The length of the second diagonal is (a) 6 cm (b) 62 cm (c) 12 cm (d) none of these

(c) 12 cm Area of the rhombus = 12 × (Product of the diagonals) Given: Length of one diagonal = 6 cm Area of the rhombus = 36 cm2 ∴ Length of the other diagonal = 36×26 cm = 12 cm

The area of a rhombus is 36 cm² and the length of one of its diagonals is 6 cm. The length of the second diagonal is

(a) 6 cm
(b) $6 \sqrt{2}$ cm
(c) 12 cm
(d) none of these

(c) 12 cm

Area of the rhombus = $\frac{1}{2}$ × (Product of the diagonals)
Given:
Length of one diagonal = 6 cm
Area of the rhombus = 36 cm²

∴ Length of the other diagonal = $(\frac{36 \times 2}{6})$ cm = 12 cm