the area of a rhombus is 72 cm square. if one of the diagonals is 18 cm, find the length of the other diagonal

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Solution

Dear Student,

$A r e a o f r h o m b u s = \frac{1}{2} \times d i a g o n a l_{1} \times d i a g o n a l_{2} 72 = \frac{1}{2} \times 18 \times d i a g o n a l_{2} d i a g o n a l_{2} = 8 c m$

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the area of a rhombus is 72 cm square. if one of the diagonals is 18 cm, find the length of the other diagonal

Dear Student, Area of rhombus=12×diagonal1×diagonal272=12×18×diagonal2diagonal2=8 cm Regards

Dear Student,

$A r e a o f r h o m b u s = \frac{1}{2} \times d i a g o n a l_{1} \times d i a g o n a l_{2} 72 = \frac{1}{2} \times 18 \times d i a g o n a l_{2} d i a g o n a l_{2} = 8 c m$

Regards