The area of a right-angled triangle is 165 sq metres. Then, find its base and altitude if the latter exceeds the former by 7 meters?
16 m and 24 m
14 m and 22 m
15 m and 22 m
16 m and 20 m
Let base = x then, altitude x + 7 ∴Area 12×x×(x+7)∴165=x(x+7)2⇒330=x2+7x⇒x2+7x−330=0(x+22)(x−15)=0⇒x=−22 and n=15∴base is x=15 mAltitude x+7=22 m