The area of a sector is 1/18th of the area of the circle The sectorial angle is

18^{\circ}

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36^{\circ}

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10^{\circ}

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20^{\circ}

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Solution

The correct option is D $20^{\circ}$
$\frac{x}{360} = \frac{1}{18} \Rightarrow x = 20^{\circ}$

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Similar questions

The area in $c m^{2}$ of a sector of a circle with radius 6 cm and angle of the sector $60^{\circ}$ is 20.

10 c m

18^{\circ}

\frac{5}{18}

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