The area of a square field is 60025 $m^{2}$ .A man cycles along its boundary at 18 km/hr.In how much time will be return a starting point.

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Solution

Area of a square field = 60025 $m^{2}$

$∴ Side of the square field(a) = \sqrt{60025} = 245 m a n d p e r i m e t e r = 4 a = 4 \times 245 m = 980 m S p e e d o f t h e m a n = 18 \frac{k m}{h r} = 18000 ∴ T i m e t a k e n = \frac{980 \times 1}{18000} h r = \frac{980 \times 1 \times 60}{18000} m i n u t e s = 3 \frac{4}{15} m i n u t e s = 3 m i n u t e s 16 s e c o n d s$

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The area of a square field is 60025 m2.A man cycles along its boundary at 18 km/hr.In how much time will be return a starting point.

Area of a square field = 60025 m2 ∴Side of the square field(a)=√60025=245 m and perimeter=4a=4×245 m=980 mSpeed of the man=18 kmhr=18000∴ Time taken=980×118000hr=980×1×6018000 minutes=3415 minutes=3 minutes 16 seconds

The area of a square field is 60025 $m^{2}$ .A man cycles along its boundary at 18 km/hr.In how much time will be return a starting point.