Question

The area of a square field is $60025m^2$. A man cycles along its boundary at $18km/h.$ In how much time will he return to the starting point?

Answer 1

Given: Area of square field $=sid{e}^2$
Side $=\sqrt{60025}{m}^2$
$=245m$
Perimeter of square field $=4\times side$
$=4\times 245m$
$=980m$

Total distance along the boundary $=$ Perimeter of the square field $=980m$

Speed is given as $8km/h.$

Speed conversion from $km/h$ to $m/sec$

$18\times \frac{5}{18}=5m/sec$

So, Time $=\frac{distance}{speed}$

$Time=\frac{980}{5}$
$=196s$.

Hence, he will return to starting point in $196$ second