The area of a square field is 60025 $m^{2}$ . A man cycles along its boundary at 18 km/hr. In how much time will he return to the starting point?

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Solution

Area of a square field = 60025 $m^{2}$
Let its side = a
$∴ a^{2} = 60025 \Rightarrow a = \sqrt{60025} \Rightarrow a = 245 m$

Perimeter= 4a= $4 \times 245 = 980 m$
Speed of cycling= 18 km/h
$∴$ Time taken to complete its boundary
= $\frac{980}{1000} \times \frac{60}{18} = \frac{49}{15}$ minutes
$= 3 \frac{4}{15} m i n u t e s .$
= 3 minutes 16 seconds

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The area of a square field is 60025 m2. A man cycles along its boundary at 18 km/hr. In how much time will he return to the starting point?

Area of a square field = 60025 m2 Let its side = a ∴a2=60025⇒a=√60025⇒a=245m Perimeter= 4a= 4×245=980m Speed of cycling= 18 km/h ∴ Time taken to complete its boundary = 9801000×6018=4915 minutes =3415minutes. = 3 minutes 16 seconds

The area of a square field is 60025 $m^{2}$ . A man cycles along its boundary at 18 km/hr. In how much time will he return to the starting point?