The area of a square field is 60025 m². A man cycles along its boundary at 18 km/hr. In how much time will he return at the starting point?

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Solution

Area of the square field = 60025 m²
The length of the square field would be the square root of 60025.
Using the long division method:

Hence, the length of the square field is 245 m.
The square has four sides, so the number of boundaries of the field is 4.
The distance s covered by the man = 245 m $\times$ 4 = 980 m = 0.98 km
If the velocity v is 18 km/hr, the required time t can be calculated using the following formula:
$t = \frac{s}{v}$
$t = {frac{0.98}{18}} = 0.054 hr=3minutes,16seconds$
So, the man will return to the starting point after 3 minutes and 16 seconds.

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The area of a square field is 60025 m2. A man cycles along its boundary at 18 km/hr. In how much time will he return at the starting point?

The area of a square field is 60025 m². A man cycles along its boundary at 18 km/hr. In how much time will he return at the starting point?