Question

The area of a square filed is $101\frac{1}{400}{m}^2$. If the length of one side of the field is $\frac{p}{q}$, where p and q are co-primes, then $p-q=?$

Answer 1

Area of a square field=$101\frac{1}{400}{m}^2$

=$\frac{40401}{400}$

Let the length of square field=$a$
$\therefore a^2=\frac{40401}{400}$
$=>a=\sqrt{\frac{40401}{400}}$
Now, lets find the value of
$\sqrt{40401}$

	$201$
$2$ $+2$	$40401$ $4$
$401$	$0401$ $401$

$\therefore \sqrt{40401}=201$ and we also have'
$\sqrt{400}=20$

Therefore

$\therefore a=\frac{201}{20}$

$p=201,$ $q=20$

$p-q$ =$201-20$

=$181$