The area of a square is $16 c m^{2}$ .Find the area of the square joining the midpoints of its sides.

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Solution

Given Area $= a^{2} = 16 c m^{2}$ & square
$x = \sqrt{{(\frac{a}{α})}^{2} + {(\frac{a}{α})}^{2}}$
$x = \frac{a}{\sqrt{2}}$
Area $= x^{2} = \frac{a^{2}}{α} = \frac{16}{α} = 8 a m^{2}$
of new square formed

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The area of a square is 16cm2.Find the area of the square joining the midpoints of its sides.

Given Area =a2=16 cm2 & squarex=√(aα)2+(aα)2x=a√2Area =x2=a2α=16α=8 am2of new square formed

The area of a square is $16 c m^{2}$ .Find the area of the square joining the midpoints of its sides.

Given Area $= a^{2} = 16 c m^{2}$ & square
$x = \sqrt{{(\frac{a}{α})}^{2} + {(\frac{a}{α})}^{2}}$
$x = \frac{a}{\sqrt{2}}$
Area $= x^{2} = \frac{a^{2}}{α} = \frac{16}{α} = 8 a m^{2}$
of new square formed