Question

The area of a square is $16c{m}^2$. The area of the rectangle with length equal to double the side of the square and breadth equal to half of the side of the square is_____

• A. 16 cm²
• B. $1600m{m}^2$
• C. $2600$$m{m}^2$
• D. $3200m{m}^2$

Answer 1

The correct option is B

$1600m{m}^2$

Area of a square = $sid{e}^2$
Here, area of the square is given as $16c{m}^2$.
$\because$ $4^2=16$, we can say that side of the square is $4cm$ long
$\therefore$ Length of the rectangle =$2\times 4$ = $8cm$ and breadth of the rectangle = $0.5\times 4$ = $2cm$
Now, area of the rectangle = $length\times breadth$ = $8\times 2$ = $16c{m}^2$

We know that $1cm=10mm$

$\therefore$ Area of rectangle = $16c{m}^2$ = $1600m{m}^2$