The area of a square is 16 cm². What will be the area of a rectangle whose length is double the side of the square and width is half of the side of the square?

16 cm²

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20 cm²

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24 cm²

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36 cm²

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Solution

The correct option is A
16 cm²

Area of square = side $\times$ side = 16 cm²
$\Rightarrow$ side of square = 4 cm
$∴$ Length of rectangle = 8 cm and breadth = 2 cm
$∴$ Area of rectangle = 8 $\times$ 2 = 16 cm^2.

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The area of a square is 16 cm2. What will be the area of a rectangle whose length is double the side of the square and width is half of the side of the square?

The correct option is A 16 cm2 Area of square = side × side = 16 cm2 ⇒ side of square = 4 cm ∴ Length of rectangle = 8 cm and breadth = 2 cm ∴ Area of rectangle = 8 × 2 = 16 cm2.

The area of a square is 16 cm². What will be the area of a rectangle whose length is double the side of the square and width is half of the side of the square?

The correct option is A
16 cm²

Area of square = side $\times$ side = 16 cm²
$\Rightarrow$ side of square = 4 cm
$∴$ Length of rectangle = 8 cm and breadth = 2 cm
$∴$ Area of rectangle = 8 $\times$ 2 = 16 cm^2.