The area of a square of side $15 c m$ is the same as that of a rectangle of width $9 c m$ . The length of the rectangle is

$16 c m$

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$18 c m$

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$20 c m$

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$25 c m$

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Solution

The correct option is D
$25 c m$

Area of rectangle $=$ area of square
Length $\times$ breadth $=$ side $\times$ side
$\Rightarrow$ Length $\times 9$ $= 15 \times 15$
$rightwards double arrow$ Length $= \frac{225}{9}$
$rightwards double arrow$ Length $= 25 c m$
Therefore, option (d) is correct

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The area of a square of side 15cm is the same as that of a rectangle of width 9cm . The length of the rectangle is

The correct option is D 25cm Area of rectangle = area of squareLength × breadth =side × side⇒Length ×9 =15×15Length =2259Length =25cm Therefore, option (d) is correct

The area of a square of side $15 c m$ is the same as that of a rectangle of width $9 c m$ . The length of the rectangle is

The correct option is D
$25 c m$

Area of rectangle $=$ area of square
Length $\times$ breadth $=$ side $\times$ side
$\Rightarrow$ Length $\times 9$ $= 15 \times 15$
$rightwards double arrow$ Length $= \frac{225}{9}$
$rightwards double arrow$ Length $= 25 c m$
Therefore, option (d) is correct