The area of a square whose sides is a diameter of a circle of area ${4 s}^{2} π$ is

{2 s}^{2}

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{4 s}^{2}

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{16 s}^{2}

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{64 s}^{2}

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Solution

The correct option is C ${16 s}^{2}$
$R a d i u s o f t h e c i r c l e = \sqrt{{4 s}^{2}} = 2 s D i a m e t e r = 4 s A r e a o f s q u a r e w h o s e s i d e i s a d i a m e t e r = 4 s \times 4 s = {16 s}^{2}$

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Question 61

State whether the following statement is true or false:

Ratio of area of a circle to the area of a square whose side equals radius of circle, is $1 : π$

4

\frac{1}{3}

\frac{1}{3}

8

π

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