The area of a trapezium (in sq. cm) whose parallel sides are 10 cm and 20 cm and the perpendicular distance between them is 5 cm is ___

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Solution

$Area of trapezium = \frac{1}{2} \times (a + b) \times h$
$= \frac{1}{2} \times 30 \times 5 = 75 c m^{2}$

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The area of a trapezium (in sq. cm) whose parallel sides are 10 cm and 20 cm and the perpendicular distance between them is 5 cm is ___

Area of trapezium=12×(a+b)×h =12×30×5=75 cm2

$Area of trapezium = \frac{1}{2} \times (a + b) \times h$
$= \frac{1}{2} \times 30 \times 5 = 75 c m^{2}$