The area of a trapezium is 1586 cm²and the distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm, then find the other parallel side.

38 cm

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23 cm

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25 cm

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Solution

The correct option is A
38 cm

Let $^{'} x^{'}$ be the required length.
Area of trapezium $= h \frac{(a + b)}{2}$ sq. units
$\Rightarrow$ $\frac{1}{2} \times (84 + x) \times 26 = 1586 c m^{2}$
$\Rightarrow x = 38 c m$

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Q. Find the area of a trapezium if the distance between its parallel sides is 26 cm and one of the parallel sides is 84 cm, the other parallel side is half of the perpendicular distance between the parallel sides.

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The area of a trapezium is 1586 cm2 and the distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm, then find the other parallel side.

The correct option is A 38 cm Let ′x′ be the required length. Area of trapezium =h(a+b)2 sq. units ⇒ 12×(84+x)×26=1586 cm2 ⇒x=38 cm

The area of a trapezium is 1586 cm²and the distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm, then find the other parallel side.

The correct option is A
38 cm

Let $^{'} x^{'}$ be the required length.
Area of trapezium $= h \frac{(a + b)}{2}$ sq. units
$\Rightarrow$ $\frac{1}{2} \times (84 + x) \times 26 = 1586 c m^{2}$
$\Rightarrow x = 38 c m$