The area of a trapezium is $198 {c m}^{2}$ and its height is $9 c m$ . If one of the parallelogram sides is longer than the other by $8 c m$ , find the two parallel sides.

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Solution

Let shorter side = x then longer side = $x + 8$
Area = $\frac{1}{2} h (a + b)$
$198 = \frac{1}{2} \times 9 \times (x + x + 8)$
$\frac{198 \times 2}{9} = 44 = 2 x + 8$
$\Rightarrow 2 x = 36$
$\Rightarrow x = 18$
$∴$ shorter side = $18 c m$
longer side = $26 c m$

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The area of a trapezium is 180 $c m^{2}$ and its height is 9 cm. If one the parallel sides is longer than the other by 6 cm, the length of the longer of the parallel sides is
(a) 17 cm (b) 23 cm
(c) 18 cm (d) 24 cm

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The area of a trapezium is 198cm2 and its height is 9cm. If one of the parallelogram sides is longer than the other by 8cm, find the two parallel sides.

Let shorter side = x then longer side = x+8Area = 12h(a+b)198=12×9×(x+x+8)198×29=44=2x+8⇒2x=36⇒x=18∴ shorter side = 18cmlonger side = 26cm

The area of a trapezium is $198 {c m}^{2}$ and its height is $9 c m$ . If one of the parallelogram sides is longer than the other by $8 c m$ , find the two parallel sides.

Let shorter side = x then longer side = $x + 8$
Area = $\frac{1}{2} h (a + b)$
$198 = \frac{1}{2} \times 9 \times (x + x + 8)$
$\frac{198 \times 2}{9} = 44 = 2 x + 8$
$\Rightarrow 2 x = 36$
$\Rightarrow x = 18$
$∴$ shorter side = $18 c m$
longer side = $26 c m$