The area of a trapezium is $210$ $i n^{2}$ and its parallel sides are $30$ in and $12$ in. Find the height.

8 i n

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9 i n

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10 i n

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11 i n

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Solution

The correct option is C $10 i n$
Area of a trapezoid = $\frac{1}{2} (b_{1} + b_{2}) \times h$
$b_{1} =$ 30 in
$b_{2} =$ 12 in
h = ?
$210$ = $\frac{1}{2} (30 + 12) \times h$
$210$ = $\frac{1}{2} \times 42 \times h$
$210 = 21 \times h$
Height, $h = 10 i n$ .

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