Question

The area of a trapezium is $240$ $f{t}^2$ and its $parallelsid{e}_1=35$ ft, $parallelsid{e}_2=13$ ft. Find the height.

• A. $10$ ft
• B. $20$ ft
• C. $30$ ft
• D. $40$ ft

Answer 1

Answer: (A)

$10$ ft

Area of a trapezoid = $\frac{1}{2}(b_1+b_2)\times h$
$b_1$= $35$ ft
$b_2$= $13$ ft
h = ?
$240$ = $\frac{1}{2}(35+13)\times h$
$240$ = $\frac{1}{2}\times 48\times h$
$240=24\times h$
Height, $h=10$ ft.