Question

The area of a trapezium is $34c{m}^2$ and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.

Answer 1

The given figure is a field at trapezium slope
Fencing will be done along the boundry i.e. the circumference of the given trapezium
$\therefore$ Length of fence = 120 m
= AB + BC + CD + AD
= AB + 48 + 17 + 40
= AB + 105
$\Rightarrow$ AB + 105 = 120
$\Rightarrow$ AB = 120 - 105
= 15 m
Since AB is perpendicular to both the parallel sides (AD and BC). AB will be the height of the given trapezium.
$Area=\frac{1}{2}\times$ sum of parallel sides $\times$ height
$=\frac{1}{2}\times (AD+BC)\times \left(AB\right)=\frac{1}{2}(40+48)\left(15\right)=\frac{88}{7}\times 15=44\times 15=660m^2$