Question

The area of a triangle is $10x^2$ and its base is $2x$. Find the length of the altitude to the base?

Answer 1

If $b$ is the base of a triangle and $h$ is the length of the altitude to the base, we know that
$\Delta =\frac{1}{2}\times b\times h$.
Here $\Delta =10x^2$ and $b=2x$. Hence
$h=\frac{2\times \Delta }{b}=\frac{2\times 10x^2}{2x}=10x$.
Hence the length of the altitude to the base is $10x$