Question

The area of a triangle is 243$c{m}^2$ and its base and height are in the ratio 3:2.Find its base and height.

• A. 9 cm, 6 cm
• B. 15 cm, 10 cm
• C. 18 cm, 12 cm
• D. 27 cm, 18 cm

Answer 1

The correct option is D 27 cm, 18 cm

Let the base and height of the triangle be 3y and 2y.
Given Area = 243$c{m}^2$.
Area of triangle = $\frac{1}{2}$$\times$base$\times$height
243 = $\frac{1}{2}$$\times$3y$\times$2y
$\frac{243}{3}$ = $y^2$ = 81
y = $\sqrt{8}1$
y = 9
Base = 3y = 27 cm, Height = 2y = 18 cm