Question

The area of a triangle is $5$ square units. Two of its vertices are $(2,1)$ and $(3,-2)$. The third vertex lies on $y=x+3$. The third vertex is

• A. $(\frac{7}{2},\frac{3}{2})$
• B. $(-\frac{3}{2},\frac{3}{2})$
• C. $(-\frac{3}{2},\frac{13}{2})$
• D. $(\frac{7}{2},\frac{5}{2})$

Answer 1

The correct option is B $(-\frac{3}{2},\frac{3}{2})$

Area of triangle $=5$
by options only B option satisfy the given condition