Question

The area of a triangle whose vertices are (2, 3), (3, 5) and (7, 5) is :

Answer 1

Given: Vertices of triangle: $(2,3),(3,5)$ and $(7,5)$

Area of triangle $=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

$=\frac{1}{2}|2(5-5)+3(5-3)+7(3-5)|$
$=\frac{1}{2}|0+6+14|$
$=\frac{1}{2}\times 20$
$=10$ sq. units