Question

The area of a triangle with a base of length $11$ units has an area of $55$ sq. units, then its height has a length of .

• A. $10$ units
• B. $5$ units
• C. $11$ units

Answer 1

The correct option is A $10$ units


Let's consider a triangle $\Delta ABC$ as shown.
Here $BC=11$ units and the area $△ABC=55$ sq. units
Now, we know the formula for calculating the area of $△ABC=\frac{1}{2}\times \text{Base}\times \text{Height}$
Here, base $BC=11$ units
Let height be $h$ units.
$\Rightarrow \frac{1}{2}\times 11\times h=55$
Dividing both sides with $11$
$\Rightarrow \frac{1}{2}\times 11\times h\times \frac{1}{11}=\frac{55}{11}$
$\Rightarrow \frac{1}{2}\times h=5$
Now, multiplying both sides with $2$
$\Rightarrow \frac{1}{2}\times h\times 2=5\times 2$
$\Rightarrow h=10$ units