Question

The area of a triangle, with sides a, b, c and semi-perimeter s, is:

• A. $\sqrt{s(s-a)(s-b)(s-c)}$
• B. $\sqrt{s(s+a)(s-b)(s-c)}$
• C. $\sqrt{s(s-a)(s+b)(s-c)}$
• D. $\sqrt{s(s-a)(s-b)(s+c)}$

Answer 1

The correct option is A

$\sqrt{s(s-a)(s-b)(s-c)}$

The semi-perimeter (s) of a triangle with sides a, b and c is given by:
$s=\frac{a+b+c}{2}$.
Then, the area (A) of the triangle can be calculated using Heron's formula, given by:
$A=\sqrt{s(s-a)(s-b)(s-c)}$.