Question

The area of a triangle, with sides $a,b,c$ and semi-perimeter $s$, is:

• A. √s(s-a)(s-b)(s-c)
• B. √s(s+a)(s-b)(s-c)
• C. √s(s-a)(s+b)(s-c)
• D. √s(s-a)(s-b)(s+c)

Answer 1

The correct option is A

√s(s-a)(s-b)(s-c)

$\text{The semi-perimeter of a triangle, s}=\frac{a+b+c}{2}$,
where $a,b$ and $c$ are the lengths of the sides of a triangle.
$\text{The area of the triangle is given as,}A=\sqrt{s(s-a)(s-b)(s-c)}$.