The area of an equilateral triangle is 43 cm 2- Its perimeter isa 9 cmb 12 cmc 123 cmd 63 cm

(b) 12 cm Area of an equilateral triangle nbsp;=34a2 nbsp;(where nbsp;a nbsp;is the length of the side) Thus, we have: 43 #160;= #160;34a2 #8658 ...

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Standard X

Mathematics

Properties of Triangles

The area of a...

Question

The area of an equilateral triangle is $4 \sqrt{3} {cm}^{2}$ . Its perimeter is
(a) 9 cm
(b) 12 cm
(c) $12 \sqrt{3}$ cm
(d) $6 \sqrt{3}$ cm

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Solution

(b) 12 cm

Area of an equilateral triangle $= \frac{\sqrt{3}}{4} a^{2}$ (where a is the length of the side)
Thus, we have:
$4 \sqrt{3} = \frac{\sqrt{3}}{4} a^{2}$
$\Rightarrow a^{2} = 16 \Rightarrow a = 4 cm$

Perimeter of the equilateral triangle = 3a $= 3 \times 4 = 12 cm$

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The area of an equilateral triangle is 43cm2. Its perimeter is (a) 9 cm (b) 12 cm (c) 123 cm (d) 63 cm

(b) 12 cm Area of an equilateral triangle =34a2 (where a is the length of the side) Thus, we have: 43 = 34a2 ⇒a2=16⇒a=4 cm Perimeter of the equilateral triangle = 3a =3×4=12 cm

The area of an equilateral triangle is $4 \sqrt{3} {cm}^{2}$ . Its perimeter is
(a) 9 cm
(b) 12 cm
(c) $12 \sqrt{3}$ cm
(d) $6 \sqrt{3}$ cm

(b) 12 cm

Area of an equilateral triangle $= \frac{\sqrt{3}}{4} a^{2}$ (where a is the length of the side)
Thus, we have:
$4 \sqrt{3} = \frac{\sqrt{3}}{4} a^{2}$
$\Rightarrow a^{2} = 16 \Rightarrow a = 4 cm$

Perimeter of the equilateral triangle = 3a $= 3 \times 4 = 12 cm$