Question

$Theareaofanequilateraltriangleis\sqrt{3}.$ $Whatistheperimeterofthetriangle?$

• A.
  $2$
• B.
  $4$
• C.
  $6$
• D.
  $8$

Answer 1

The correct option is C

$6$
$Areaofanequilateraltriangle=\sqrt{3}$

$\frac{\sqrt{3}}{4}{a}^2=\sqrt{3}$

$a^2=4$

$a=2$

$\text{Perimeter}=3a=3\times 2=6$