Question

The area of an equilateral triangle of side $\text{8 cm}$ is ${cm}^2$.

• A. $6\sqrt{3}$
• B. $16\sqrt{3}$
• C. $16\sqrt{5}$

Answer 1

The correct option is B $16\sqrt{3}$

Area of an equilateral triangle whose side is 8 cm long is given by
$\frac{\sqrt{3}}{4}{a}^2$ ${cm}^2$, where a $=\text{8 cm}$
Area of the equilateral triangle
$=\frac{\sqrt{3}}{4}\times 8^2{cm}^2$
$=\frac{\sqrt{3}}{4}\times 64{cm}^2$
$=16\sqrt{3}{cm}^2$