Question

The area of an isosceles trapezium is $34c{m}^2$ and the length of one of the parallel sides is 10 cm and Its height is 4 cm. Find the length of the other parallel side.

• A. 4 cm.
• B. 7 cm.
• C. 9 cm.
• D. 10 cm.

Answer 1

The correct option is B

7 cm.

Let the length of the other parallel side be b
Length of one parallel side (a) = 10 am and height (h) = 4 cm
Area of trapezium = $\frac{1}{2}(a+b)\times h$
$\Rightarrow 34=\frac{1}{2}(10+b)\times 4\Rightarrow 34=(10+b)\times 2\Rightarrow 34=20+2b\Rightarrow 34-20=2b\Rightarrow 14=2b\Rightarrow 7=b\Rightarrow b=7$
Hence an other required parallel sides is 7 cm.