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Question

The area of an isosceles trapezium is 34cm2 and the length of one of the parallel sides is 10 cm and Its height is 4 cm. Find the length of the other parallel side.


A

4 cm.

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B

7 cm.

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C

9 cm.

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D

10 cm.

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Solution

The correct option is C

7 cm.


Let the length of the other parallel side be b
Length of one parallel side (a) = 10 am and height (h) = 4 cm
Area of trapezium = 12(a+b)×h
34=12(10+b)×4 34=(10+b)×234=20+2b 3420=2b14=2b 7=bb=7
Hence an other required parallel sides is 7 cm.


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