Question

The area of cross section of a large tank is $0.5m^2$.It has a opening near the bottom having area of cross section $1c{m}^2$.A load of 20 kg is applied on the water at the top.Find the velocity of the water coming out of the opening at the time when the height of the water level is50 cm above the bottom.Taking g=$10m/s^2$.

• A. 3.3
  
• B. 2.3
  
• C. 1.3
  
• D. 4.3
  

Answer 1

The correct option is A 3.3

As the area of cross section of the tank is large compared to that of the opening the speed of water in the tank will be very small as compared to the speed of the opening. The pressure at the surface of the water in the tank is that due to the atmosphere plus due to the load.

$\Rightarrow P_A=P_0+\frac{\left(20kg\right)\left(10m/s^2\right)}{0.5m^2}=P_0+400N/m^2$

At the opening, the pressure is that due to the atmosphere.

Using Bernoulli equation -

$\Rightarrow P_A+Pgh+\frac{1}{2}P{V}_A^2=P_B+\frac{1}{2}P{V}_B^2$

$\Rightarrow P_0+400N/m^2+\left(1000kg/m^2\right)\left(10m/s^2\right)\left(0.5m\right)+0$$=P_0+\frac{1}{2}\left(1000kg{m}^{-3}\right)V_B^2$

$\Rightarrow 5400N/m^2={\left(500kg/m\right)}^3{V}_B^3$

$\Rightarrow V_B=3.3m/s$

Hence, the answer is $3.3m/s.$