Question

The area of cross section of press plunger of hydraulic press is 4$m^2$. It is required to overcome a resistive load of 400N on it.If the area of cross section of pump plunger is 0.01$m^2$ then force required on pump plunger is

• A. 0.1N
• B. 10N
• C. 1N
• D. 100N

Answer 1

The correct option is C

1N

Area of cross section of pump plunger $A_1=0.01m^2$, Area of cross section of press plunger $A_2=4m^2$, Resistive force of press plunger $F_2=400N$ and Force required on pump plunger $=F_1$

According to Pascal law

$\frac{F_1}{A_1}=\frac{F_2}{A_2}\Rightarrow \frac{F_1}{F_2}=\frac{A_1}{A_2}\Rightarrow \frac{F_1}{400}=\frac{0.01}{4}\Rightarrow F_1=1\text{Newton}$