The area of cross-section of the wider tube show in figure is 800cm2. If a mass of 12kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is :
Given that:
A=800cm2
m=12kg=12000g
Here, the force on piston is F=mg
Hence, increase in pressure on the liquid in the wider tube is
P=FA=mgA
Since, h is the difference in level of water in the two tubes, thus
P=hρg
h=Pρg
h=mgAρg=mAρ
h=12000800.......(∵ρ=1)
∴h=15cm