Question

The area of cross section of the wider tube shown in figure is 900 $c{m}^2$. If the boy standing on the piston weighs 45 kg, find the difference in the levels of water in the two tubes.

Answer 1

$P_1-P_2=pgh$

mg = 1000 $\times g\times hA$

$\Rightarrow h\frac{m}{1000\times A}$

= $\frac{45}{1000\times 900\times {10}^{-4}}$

= $\frac{1}{2}m$ = 50 cm