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Volume of a Hollow Cylinder

The area of c...

Question

The area of cross section of the wider tube shown in figure is $900 {c m}^{2}$ . If a mass of $45 k g$ is placed on the massless piston, the difference in heights $h$ in the level of water in the two tubes is:

10 c m

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50 c m

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15 c m

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2 c m

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Solution

The correct option is B $50 c m$
$\begin{matrix} F r o m f i g u r e P_{B} = P_{C} P_{a} + ρ h g = P_{a} + \frac{m g}{A} \Rightarrow h = \frac{m}{A ρ} h = \frac{45 k g}{1000 k g / m^{3} \times 900 c m^{2}} h = 50 c m \end{matrix}$
Hence,
option $(B)$ is correct answer.

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The area of cross section of the wider tube shown in figure is 900cm2. If a mass of 45kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is:

The correct option is B 50cmFromfigurePB=PCPa+ρhg=Pa+mgA⇒h=mAρh=45kg1000kg/m3×900cm2h=50cmHence,option (B) is correct answer.

The area of cross section of the wider tube shown in figure is $900 {c m}^{2}$ . If a mass of $45 k g$ is placed on the massless piston, the difference in heights $h$ in the level of water in the two tubes is:

The correct option is B $50 c m$
$\begin{matrix} F r o m f i g u r e P_{B} = P_{C} P_{a} + ρ h g = P_{a} + \frac{m g}{A} \Rightarrow h = \frac{m}{A ρ} h = \frac{45 k g}{1000 k g / m^{3} \times 900 c m^{2}} h = 50 c m \end{matrix}$
Hence,
option $(B)$ is correct answer.