Question

The area of cross section of two cylinders of a Hydraulic press are $10c{m}^2$ and $50c{m}^2$ respectively. In order to move up a weight of 100 N placed on the piston of larger area of the press, force supplied on the piston of smaller area is $(y\times 10)$ Newton. Find 'y'.

Answer 1

Given $a_1=10c{m}^2$ and $a_2=50c{m}^2$
Also given $F_2=100N,F_1=?$
Pressure is equal on both the pistons $\Rightarrow P_1=P_2$
$\Rightarrow \frac{F_1}{a_1}=\frac{F_2}{a_2}$
$\Rightarrow F_1=\left(\frac{F_2}{a_2}\right)a_1=\left(\frac{100}{50}\right)1020N$
Thus 20 N force applied on the piston of smaller area is sufficient to lift a weight of 100 N placed on the piston of larger area.