The area of - ABC in which AB-BC- 4cm and - B- 90- is -

The correct option is B 8 cm^2 Area #160; ABC= 1 2 × BC× AB= 1 2 × 4× 4=8 cm ^ 2 ...

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The area of ...

Question

The area of $Δ A B C$ in which $A B = B C = 4 c m$ and $∠ B = 90^{\circ}$ is :

16 c m^{2}

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8 c m^{2}

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4 c m^{2}

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12 c m^{2}

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Solution

The correct option is B $8 c m^{2}$

Area $△ A B C = \frac{1}{2} \times B C \times A B = \frac{1}{2} \times 4 \times 4 = 8 {c m}^{2}$

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Similar questions

Q. The area of

Δ A B C

in which

A B = B C = 4 c m

and

∠ B = 90^{0}

is :

If $Δ A B C \sim Δ D E F$ such that area of $Δ A B C$ is $9 c m^{2}$ and the area of $Δ D E F$ is $16 c m^{2}$ and BC = 2.1 cm. Find the length of EF. [2 MARKS]

Q. Question 2
Write True or False and justify your answer:

The area of a

Δ A B C

is 8

c m^{2}

in which AB = AC = 4 cm and

∠ A = 90^{\circ}

Q. In

Δ A B C

∠ B = 90^{\circ}

, Find the sides of the triangle, if

A B = x c m, B C = (4 x + 4) c m

and

A C = (4 x + 5) c m

Q. Draw ∆ ABC in which ∠C = 90° and AC = BC = 4 cm.

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The area of ΔABC in which AB=BC=4cm and ∠B=90∘ is :

The correct option is B 8cm2Area △ABC=12×BC×AB=12×4×4=8cm2

The area of $Δ A B C$ in which $A B = B C = 4 c m$ and $∠ B = 90^{\circ}$ is :

The correct option is B $8 c m^{2}$

Area $△ A B C = \frac{1}{2} \times B C \times A B = \frac{1}{2} \times 4 \times 4 = 8 {c m}^{2}$