The area of figure 1 (in $c m^{2}$ ) and area of figure 2 (in $c m^{2}$ ) are _ and _ respectively.

Open in App

Solution

Area of trapezium = h $\frac{(a + b)}{2}$ sq. units

= $\frac{1}{2}$ $\times$ (8 + 6) $\times$ 3 = 21 $c m^{2}$

Area of triangle = $\frac{1}{2}$ $\times$ b $\times$ h = $\frac{1}{2}$ $\times$ 14 $\times$ 3 = 21 $c m^{2}$

Suggest Corrections

Similar questions

The area of figure 1 (in $c m^{2}$ ) and area of figure 2 (in $c m^{2}$ ) are ___ and ___ respectively.

The area of figure 1 (in $c m^{2}$ ) and area of figure 2 (in $c m^{2}$ ) are __ and __ respectively.

The areas of figure 1 (in $c m^{2}$ ) and figure 2 (in $c m^{2}$ ) are __ and __ respectively.

196 c m^{2}

144 c m^{2}

c m^{2}

Join BYJU'S Learning Program