The area of figure 1 (in $c m^{2}$ ) and area of figure 2 (in $c m^{2}$ ) are _ and _ respectively.

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Solution

Area of trapezium $= h \frac{(a + b)}{2}$ sq. units

$= \frac{1}{2} \times (8 + 6) \times 3 = 21 c m^{2}$

Area of triangle $= \frac{1}{2} \times b \times h = \frac{1}{2} \times 14 \times 3 = 21 c m^{2}$

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